Oracle中如何手工提交ClusterTable的事务 - 数据库编程

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Oracle中如何手工提交ClusterTable的事务(三)

2015-07-24 11:28:45 来源: 作者: 【大中小】浏览:18次

otal Blocks Processed (Index): 0

Total Blocks Failing (Index): 0 Total Blocks Empty : 0 Total Blocks Marked Corrupt : 0 Total Blocks Influx : 0 Message 531 not found; product=RDBMS; facility=BBED BBED> d /v offset 106 File: /oracle/oradata/roger/roger01.dbf (6) Block: 174 Offsets: 106 to 109 Dba:0x018000ae ------------------------------------------------------- 1a00781f l ..x. <16 bytes per line> BBED> modify /x 18 offset 106 File: /oracle/oradata/roger/roger01.dbf (6) Block: 174 Offsets: 106 to 109 Dba:0x018000ae ------------------------------------------------------------------------ 1800781f <32 bytes per line> BBED> sum apply Check value for File 6, Block 174: current = 0x054d, required = 0x054d BBED> verify DBVERIFY - Verification starting FILE = /oracle/oradata/roger/roger01.dbf BLOCK = 174 Block Checking: DBA = 25165998, Block Type = KTB-managed data block data header at 0x1112864 kdbchk: row count in table index incorrect Block 174 failed with check code 6125 DBVERIFY - Verification complete Total Blocks Examined : 1 Total Blocks Processed (Data) : 1 Total Blocks Failing (Data) : 1 Total Blocks Processed (Index): 0 Total Blocks Failing (Index): 0 Total Blocks Empty : 0 Total Blocks Marked Corrupt : 0 Total Blocks Influx : 0 Message 531 not found; product=RDBMS; facility=BBED BBED> p kdbt struct kdbt[0], 4 bytes @114 sb2 kdbtoffs @114 0 sb2 kdbtnrow @116 1 struct kdbt[1], 4 bytes @118 sb2 kdbtoffs @118 1 sb2 kdbtnrow @120 1 BBED> p kdbt[1] struct kdbt[1], 4 bytes @118 sb2 kdbtoffs @118 1 sb2 kdbtnrow @120 1 BBED> d /v offset 118 count 4 File: /oracle/oradata/roger/roger01.dbf (6) Block: 174 Offsets: 118 to 121 Dba:0x018000ae ------------------------------------------------------- 01000100 l .... <16 bytes per line> BBED> modify /x 000000 offset 118 File: /oracle/oradata/roger/roger01.dbf (6) Block: 174 Offsets: 118 to 121 Dba:0x018000ae ------------------------------------------------------------------------ 00000000 <32 bytes per line> BBED> sum apply Check value for File 6, Block 174: current = 0x054d, required = 0x054d BBED> verify DBVERIFY - Verification starting FILE = /oracle/oradata/roger/roger01.dbf BLOCK = 174 Block Checking: DBA = 25165998, Block Type = KTB-managed data block data header at 0x1112864 kdbchk: table index offset incorrect tab 1 Block 174 failed with check code 6124 DBVERIFY - Verification complete Total Blocks Examined : 1 Total Blocks Processed (Data) : 1 Total Blocks Failing (Data) : 1 Total Blocks Processed (Index): 0 Total Blocks Failing (Index): 0 Total Blocks Empty : 0 Total Blocks Marked Corrupt : 0 Total Blocks Influx : 0 Message 531 not found; product=RDBMS; facility=BBED

我们可以看到，无论怎么修改，这个block通过bbed进行检测都报错，这里不是因为修改的不对,而是因为
还需要修改cluster 上的Index信息。通过treedump 我们可以确认index block为file 6 block 187.

+++++ dump Index block

1 2 3 4 5 6 7 8 9 10 11 SQL> oradebug setmypid Statement processed. SQL> alter system dump datafile 6 block 187; System altered. SQL> oradebug close_trace Statement processed. SQL> oradebug tracefile_name /oracle/diag/rdbms/roger/roger/trace/roger_ora_17394.trc SQL>

+++++ dump 内容如下

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 Block header dump: 0x018000bb Object id on Block? Y seg/obj: 0x12ed2 csc: 0x00.b941a3 itc: 2 flg: E typ: 2 - INDEX brn: 0 bdba: 0x18000b8 ver: 0x01 opc: 0 inc: 0 exflg: 0 Itl Xid Uba Flag Lck Scn/Fsc 0x01 0x0000.000.00000000 0x00000000.0000.00 ---- 0 fsc 0x0000.00000000 0x02 0x0009.002.0000044c 0x00c000f9.014a.1e --U- 1 fsc 0x0000.00b941a4 Leaf block dump =============== header address 1405

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