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非IMU模式下一条update语句产生REDORECORD条数的探究(四)
2014-11-24 07:45:21 来源: 作者: 【 】 浏览:14
Tags:IMU 模式 update 语句 产生 REDORECORD 探究
x: 0
ncol: 3 nnew: 1 size: -2
col 1: [ 4] 74 65 73 74
CHANGE #2 TYP:0 CLS:1 AFN:4 DBA:0x010000fd OBJ:22327 SCN:0x0000.00704cb2 SEQ:3 OP:11.5 ENC:0 RBL:0
KTB Redo
op: 0x02 ver: 0x01
compat bit: 4 (post-11) padding: 1
op: C uba: 0x00c02e0e.0247.2d
KDO Op code: URP row dependencies Disabled
xtype: XA flags: 0x00000000 bdba: 0x010000fd hdba: 0x010000fa
itli: 1 ispac: 0 maxfr: 4858
tabn: 0 slot: 6(0x6) flag: 0x2c lock: 1 ckix: 0
ncol: 3 nnew: 1 size: 2
col 1: [ 6] 6f 72 61 63 6c 65
################################################提交的日志条目:
REDO RECORD - Thread:1 RBA: 0x00013b.0000002c.0010 LEN: 0x008c VLD: 0x05
SCN: 0x0000.00704cb4 SUBSCN: 1 01/06/2014 22:04:43
(LWN RBA: 0x00013b.0000002c.0010 LEN: 0001 NST: 0001 SCN: 0x0000.00704cb3)
CHANGE #1 TYP:0 CLS:33 AFN:3 DBA:0x00c00100 OBJ:4294967295 SCN:0x0000.00704cb2 SEQ:1 OP:5.4 ENC:0 RBL:0
ktucm redo: slt: 0x0015 sqn: 0x00000e9f srt: 0 sta: 9 flg: 0x2 ktucf redo: uba: 0x00c02e0e.0247.2d ext: 8 spc: 2704 fbi: 0
END OF REDO DUMP

实验2的:

REDO RECORD - Thread:1 RBA: 0x00013a.00000002.0010 LEN: 0x01c0 VLD: 0x05
SCN: 0x0000.00703bc1 SUBSCN: 1 01/06/2014 21:56:03
(LWN RBA: 0x00013a.00000002.0010 LEN: 0002 NST: 0001 SCN: 0x0000.00703bc0)
CHANGE #1 TYP:0 CLS:23 AFN:3 DBA:0x00c000b0 OBJ:4294967295 SCN:0x0000.00703b80 SEQ:1 OP:5.2 ENC:0 RBL:0
ktudh redo: slt: 0x0004 sqn: 0x00000ec7 flg: 0x0012 siz: 168 fbi: 0
uba: 0x00c01ddb.0283.21 pxid: 0x0000.000.00000000
CHANGE #2 TYP:0 CLS:24 AFN:3 DBA:0x00c01ddb OBJ:4294967295 SCN:0x0000.00703b7f SEQ:9 OP:5.1 ENC:0 RBL:0
ktudb redo: siz: 168 spc: 3658 flg: 0x0012 seq: 0x0283 rec: 0x21
xid: 0x0004.004.00000ec7
ktubl redo: slt: 4 rci: 0 opc: 11.1 [objn: 22327 objd: 22327 tsn: 4]
Undo type: Regular undo Begin trans Last buffer split: No
Temp Object: No
Tablespace Undo: No
0x00000000 prev ctl uba: 0x00c01ddb.0283.01
prev ctl max cmt scn: 0x0000.007034c7 prev tx cmt scn: 0x0000.007034f1
txn start scn: 0xffff.ffffffff logon user: 32 prev brb: 12590550 prev bcl: 0 BuExt idx: 0 flg2: 0
KDO undo record:
KTB Redo
op: 0x04 ver: 0x01
compat bit: 4 (post-11) padding: 1
op: L itl: xid: 0x0003.013.00000eac uba: 0x00c01ac7.0250.06
flg: C--- lkc: 0 scn: 0x0000.00702d7a
KDO Op code: URP row dependencies Disabled
xtype: XA flags: 0x00000000 bdba: 0x010000fd hdba: 0x010000fa
itli: 2 ispac: 0 maxfr: 4858
tabn: 0 slot: 2(0x2) flag: 0x2c lock: 0 ckix: 0
ncol: 3 nnew: 1 size: 2 ---ACCOUNTING 比database多两个字节
col 1: [10] 41 43 43 4f 55 4e 54 49 4e 47 ---对应的是将第一行第二列的值放进UNDO---ACCOUNTING
CHANGE #3 TYP:0 CLS:1 AFN:4 DBA:0x010000fd OBJ:22327 SCN:0x0000.00703bb3 SEQ:3 OP:11.5 ENC:0 RBL:0
KTB Redo
op: 0x01 ver: 0x01
compat bit: 4 (post-11) padding: 1
op: F xid: 0x0004.004.00000ec7 uba: 0x00c01ddb.0283.21
KDO Op code: URP row dependencies Disabled
xtype: XA flags: 0x00000000 bdba: 0x010000fd hdba: 0x010000fa
itli: 2 ispac: 0 maxfr: 4858
tabn: 0 slot: 2(0x2) flag: 0x2c lock: 2 ckix: 0
ncol: 3 nnew: 1 size: -2
col 1: [ 8] 64 61 74 61 62 61 73 65

REDO RECORD - Thread:1 RBA: 0x00013a.00000002.01d0 LEN: 0x0190 VLD: 0x01 --这个REDO RECORD只有CHANGE #1,CHANGE #2
SCN: 0x0000.00703bc1 SUBSCN: 1 01/06/2014 21:56:03
CHANGE #1 TYP:0 CLS:24 AFN:3 DBA:0x00c01ddb OBJ:4294967295 SCN:0x0000.00703bc1 SEQ:1 OP:5.1 ENC:0 RBL:0
ktudb redo: siz: 164 spc: 3488 flg: 0x0022 seq: 0x0283 rec: 0x22
xid: 0x0004.004.00000ec7
ktubu redo: slt: 4 rci: 33 opc: 11.1 objn: 22327 objd: 22327 tsn: 4
Undo type: Regular undo Undo type: Last buffer split: No
Tablespace Undo: No
0x00000000
KDO undo record:
KTB Redo
op: 0x02 ver: 0x01
compat bit: 4 (post-11) padding: 1
op: C uba: 0x00c01ddb.0283.2

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