Oracle如何修改列的数据类型(一)

2014-11-24 09:26:07 · 作者: · 浏览: 2
Oracle如何修改列的数据类型
对字段操作 操作方法
更新字段名 alter table TABLE_NAME rename column column_old to column_new;
添加字段 alter table TABLE_NAME add COLUMN_NAME varchar(10);
删除字段 alter table TABLE_NAME drop column COLUMN_NAME;
添加字段并附值 alter table TABLE_NAME ADD COLUMN_NAME NUMBER(1) DEFAULT 1;
修改字段值 update TABLE_NAME set filedname=value where filedname=value;
修改字段数据类型 alter table tablename modify filedname varchar2(20);

1 SQL> select * from v$version;
2 
3 BANNER
4 --------------------------------------------------------------------------------
5 Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
6 PL/SQL Release 11.2.0.1.0 - Production
7 CORE    11.2.0.1.0      Production
8 TNS for Linux: Version 11.2.0.1.0 - Production
9 NLSRTL Version 11.2.0.1.0 - Production

1.修改字段数据类型时,如果该列有数据则报ORA-01439: column to be modified must be empty to change datatype,此时需要通过另外一种方法修改:
 1 SQL> alter table zyt add id_temp varchar2(10);
 2 
 3 Table altered.
 4 
 5 SQL> commit;
 6 
 7 Commit complete.
 8 
 9 SQL> select * from zyt;
10 
11 NAME               ID ID_TEMP
12 ---------- ---------- ----------
13 zyt1                1
14 david               2
15 
16 SQL> alter table zyt rename column id to id_bak;
17 
18 Table altered.
19 
20 SQL> select * from zyt;
21 
22 NAME           ID_BAK ID_TEMP
23 ---------- ---------- ----------
24 zyt1                1
25 david               2
26 
27 SQL> desc zyt;
28  Name                                      Null     Type
29  ----------------------------------------- -------- ----------------------------
30  NAME                                               VARCHAR2(10)
31  ID_BAK                                    NOT NULL NUMBER(2)
32  ID_TEMP                                            VARCHAR2(10)
33 
34 SQL> update zyt set ID_TEMP = cast(ID_BAK as varchar2(10));
35 
36 2 rows updated.
37 
38 SQL> commit;
39 
40 Commit complete.
41 
42 SQL> select * from zyt;
43 
44 NAME           ID_BAK ID_TEMP
45 ---------- ---------- ----------
46 zyt1                1 1
47 david               2 2
48 
49 SQL>  alter table zyt drop column ID_BAK;
50 
51 Table altered.
52 
53 SQL> commit;
54 
55 Commit complete.
56 
57 SQL> select * from zyt;
58 
59 NAME       ID_TEMP
60 ---------- ----------
61 zyt1       1
62 david      2
63 
64 SQL> desc zyt;
65  Name                                      Null     Type
66  ----------------------------------------- -------- ----------------------------
67  NAME                                               VARCHAR2(10)
68  ID_TEMP                                            VARCHAR2(10)

备注:这种方法能满足需求,因新增字段默认添加到表末尾,有可能发生行迁移,对应用程序会产生影响,同时也涉及复杂数据,不算最好的方法
2.建立一个中间跳板,临时存储数据
 1 SQL> desc zyt;
 2  Name                                      Null     Type
 3  ----------------------------------------- -------- ----------------------------
 4  NAME                                               VARCHAR2(10)
 5  ID                                                 VARCHAR2(10)
 6 
 7 SQL> select * from zyt;
 8 
 9 NAME       ID
10 ---------- ----------
11 zyt1       1
12 david      2
13 
14 SQL> alter table zyt add id_temp VARCHAR2(10)
15 
16 Table altered.
17 
18 SQL> select * from zyt;
19 
20 NAME       ID            ID_TEMP
21 ---------- ---------- ----------
22 zyt1       1
23 david      2
24 
25 SQL> update zyt set ID_TEMP=id,id=null;
26 
27 2 rows updated.
28 
29 SQL> select * from zyt;
30 
31 NAME       ID            ID_TEMP
32 ---------- ---------- ----------
33 zyt1                           1
34 david                          2
35 
36 SQL> alter table zyt modify id number(10);
37 
38 Table altered.
39 
40 SQL> desc zyt;
41  Name                                      Null     Type
42  ----------------------------------------- -------- ----------------------------
43  NAME                                               VARCHAR2(10)
44  ID                                                 NUMBER(10)
45  ID_TEMP                                            VARCHAR2(10)
46 
47 SQL> update zyt set id=ID_TEMP,ID_TEMP=null;
48 
49 2 rows updated.
50 
51 SQL> select * from zyt;
52 
53 NAME               ID    ID_TE