head的值也有了改变， 故需要把这个指针返回主调函数。
[例7.14]将以上建立链表，删除结点，插入结点的函数组织在一起，再建一个输出全部结点的函数，然后用main函数调用它们。
#define NULL 0
#define TYPE struct stu
#define LEN sizeof(struct stu)
struct stu
{
int num;
int age;
struct stu *next;
};
TYPE * creat(int n)
{
struct stu *head,*pf,*pb;
int i;
for(i=0;i<n;i++)
{
pb=(TYPE *)malloc(LEN);
printf("input Number and Age\n");
scanf("%d%d",&pb->num,&pb->age);
if(i==0)
pf=head=pb;
else pf->next=pb;
pb->next=NULL;
pf=pb;
}
return(head);
}
TYPE * delete(TYPE * head,int num)
{
TYPE *pf,*pb;
if(head==NULL)
{ printf("\nempty list!\n");
goto end;}
pb=head;
while (pb->num!=num && pb->next!=NULL)
{pf=pb;pb=pb->next;}
if(pb->num==num)
{ if(pb==head) head=pb->next;
else pf->next=pb->next;
printf("The node is deleted\n"); }
else
free(pb);
printf("The node not been found!\n");
end:
return head;
}
TYPE * insert(TYPE * head,TYPE * pi)
{
TYPE *pb ,*pf;
pb=head;
if(head==NULL)
{ head=pi;
pi->next=NULL; }
else
{
while((pi->num>pb- |