Oracle里时间的应用(四)

2014-11-24 12:51:17 · 作者: · 浏览: 3
yy || '-' || to_char(ww * 7), 'yyyy-ddd')), 'd') last_day

from (select substr('2004-32', 1, 4) yy, to_number(substr('2004-32', 6)) ww

from dual)

select trunc(to_date(substr('2003-01',1,5)||to_char((to_number(substr('2003-01',6)))*7),'yyyy-ddd'),'d')-6 first_day from dual

select min(v_date) from

(select (to_date('200201','yyyymm') + rownum) v_date

from all_tables

where rownum < 370)

where to_char(v_date,'yyyy-iw') = '2002-49'

2.查询某周的最后一天

select trunc(decode(ww, 53, to_date(yy || '3112', 'yyyyddmm'), to_date(yy || '-' || to_char(ww * 7), 'yyyy-ddd')), 'd') - 6 first_day

from (select substr('2004-33', 1, 4) yy, to_number(substr('2004-33', 6)) ww

from dual)

select trunc(to_date(substr('2003-01',1,5)||to_char((to_number(substr('2003-01',6)))*7),'yyyy-ddd'),'d') last_day from dual

select max(v_date) from

(select (to_date('200408','yyyymm') + rownum) v_date

from all_tables

where rownum < 370)

where to_char(v_date,'yyyy-iw') = '2004-33'

3.查询某周的日期

select min_date, to_char(min_date,'day') day from

(select to_date(substr('2004-33',1,4)||'001'+rownum-1,'yyyyddd') min_date

from all_tables

where rownum <= decode(mod(to_number(substr('2004-33',1,4)),4),0,366,365)

union

select to_date(substr('2004-33',1,4)-1||

decode(mod(to_number(substr('2004-33',1,4))-1,4),0,359,358)+rownum,'yyyyddd') min_date

from all_tables

where rownum <= 7

union

select to_date(substr('2004-33',1,4)+1||'001'+rownum-1,'yyyyddd') min_date

from all_tables

where rownum <= 7

)

where to_char(min_date,'yyyy-iw') ='2004-33'

摘自 幸福的猪的专栏