在上一个练习学习了如何使用Jersey,以及JAXB来创建RESTful的web service。
现在我来结合后台数据库对其做升级,也就是通过Jersey创建用来修改后台数据库的RESTful web service。
开发环境:
Eclipse Juno, 数据库MySQL 5.5, Jersey 1.18,EclipseLink 2.4, JAVA 1.6, 应用服务器Tomcat 7。
1.创建一个叫做jersey3的Dynamic Web Project。添加JPA的facet。
2.导入Jersey包,导入EclipseLink包,导入MySQL的connect包。
3.开发数据库对象,配置JPA。
数据对象Employee类:
package sample;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
@Entity
@Table(name = "employee")
public class Employee {
@Id
@Column(name = "userId")
private Long id;
@Column(name = "firstName")
private String firstName;
@Column(name = "lastName")
private String lastName;
public long getId() {
return id;
}
public void setId(long id) {
this.id = id;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
}
persistence.xml:

< xml version="1.0" encoding="UTF-8" >org.eclipse.persistence.jpa.PersistenceProvider sample.Employee
4.配置Jersey,编写代码来实现RESTful web service。
创建web.xml:
< xml version="1.0" encoding="UTF-8" >RestProjectTest Jersey REST Service com.sun.jersey.spi.container.servlet.ServletContainer com.sun.jersey.config.property.packages sample com.sun.jersey.api.json.POJOMappingFeature true 1 Jersey REST Service /* sample.LocalEntityManagerFactory
可以来管理我们的EntityManager。
package sample;
import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.Persistence;
import javax.servlet.ServletContextEvent;
import javax.servlet.ServletContextListener;
import javax.servlet.annotation.WebListener;
@WebListener
public class LocalEntityManagerFactory implements ServletContextListener {
private static EntityManagerFactory emf;
@Override
public void contextInitialized(ServletContextEvent event) {
emf = Persistence.createEntityManagerFactory("EmployeePU");
System.out.println("ServletContextListener started");
}
@Override
public void contextDestroyed(ServletContextEvent event) {
emf.close();
System.out.println("ServletContextListener destroyed");
}
public static EntityManager createEntityManager() {
if (emf == null) {
throw new IllegalStateException("Context is not initialized yet.");
}
return emf.createEntityManager();
}
} 开发好JPA相关的持久化功能后,就可以来实现RESTful service了,代码:
package sample;
import java.util.List;
import javax.persistence.EntityManager;
import javax.persistence.Query;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
@Path("/employee")
public class EmployeeController {
@GET
@Produces({ MediaType.TEXT_XML })
@Path("{id}")