SQL自定义Split函数(二)
E @next int;
5 set @next=1
6
7 DECLARE @Length int;
8 SELECT @Length=dbo.GetSplitLength(@Tags,',')
9
10 while @next<=@Length
11 begin
12 SET @Tag = left(dbo.GetSplitOfIndex(@Tags,',',@next), 16);
13 print @Tag
14 SET @Next=@Next+1;
15 END
结果为：
111
b2222
323232
32d
e
323232f
g3222