1.将1.txt的内容分离为3个文件(金额、身份证、代号).
2.为保证游戏公平,请将代码写为一行.(鉴于一些语言特性，直接计算代码文件大小)
3.代码数最少即为获胜(计算空格).

1.txt
1234567890|312|32145
1234567890|312|32145
1234567890|312|32145
1234567890|312|32145
1234567890|312|32145
1234567890|312|32145
1234567890|312|32145
1234567890|312|32145

1234567890 输出到 身份证.txt
312 输出到 金额.txt
21145 输出到 代号.txt

下面是我用c写的view plaincopy to clipboardprint
#include
#include <windows.h>

FILE* G;
char* wN[6] = {"身份证:","金额:","代号:","身份证.txt","金额.txt","代号.txt"};

main(int argc,char* argv[]){
if(argc == 2){
char T[256];
char w[64];
FILE* f;
char* p;
int i;
f = fopen(argv[1],"r");
while(fgets(T,80,f)){
i = 0;
p = strtok(T,"|");
while(p != 0){
sprintf(w,"%s%s%s",wN[i],p,i<2 " ":""); //需要处理换行
G = fopen(wN[i+3],"a+");
fwrite(w,strlen(w),1,G);
fclose(G);
p = strtok(0,"|");
i++;
}
}
}
}
#include
#include

FILE* G;
char* wN[6] = {"身份证:","金额:","代号:","身份证.txt","金额.txt","代号.txt"};

main(int argc,char* argv[]){
if(argc == 2){
char T[256];
char w[64];
FILE* f;
char* p;
int i;
f = fopen(argv[1],"r");
while(fgets(T,80,f)){
i = 0;
p = strtok(T,"|");
while(p != 0){
sprintf(w,"%s%s%s",wN[i],p,i<2 " ":""); //需要处理换行
G = fopen(wN[i+3],"a+");
fwrite(w,strlen(w),1,G);
fclose(G);
p = strtok(0,"|");
i++;
}
}
}
}
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感觉还是脚本写的代码简短，同事用python写代码的只有256字节，我这居然有500+字节