和为s的连续正整数序列 代码(C)
?
?
题目: 输入一个正数s, 打印出所有和为s的连续正数序列(至少含有两个数).
?
起始于1, 2, 相加, 如果相等则返回, 如果小于, 则前端递增右移, 如果大于, 则后端递增右移, 一直到后端移动到s的一半位置.
因为两个数, 小数为一半, 大数为一半加一, 则必然结束.
?
代码:
?
/*
* main.cpp
*
* Created on: 2014.6.12
* Author: Spike
*/
/*eclipse cdt, gcc 4.8.1*/
#include
#include
#include
void PrintContinuousSequence(int small, int big) { for (int i=small; i<=big; ++i) printf(%d , i); printf( ); } void FindContinuousSequence(int sum) { if (sum<3) return; int small = 1; int big = 2; int middle = (1+sum)/2; int curSum = small+big; while (small < middle) { if (curSum == sum) PrintContinuousSequence(small, big); while (curSum > sum && small < middle) { curSum -= small; small++; if(curSum == sum) PrintContinuousSequence(small, big); } big++; curSum += big; } } int main(void) { FindContinuousSequence(15); return 0; }
输出:
?
?
1 2 3 4 5
4 5 6
7 8
?
?
?
?