value r?-?l takes the maximum value among all pairs for which condition 1 is true; Help Simon, find the required pair of numbers (l,?r). If there are multiple required pairs find all of them.
Input The first line contains integer n (1?≤?n?≤?3·105).
The second line contains n space-separated integers a1,?a2,?...,?an (1?≤?ai?≤?106).
Output Print two integers in the first line — the number of required pairs and the maximum value of r?-?l. On the following line print all l values from optimal pairs in increasing order.
Sample test(s) input
5
4 6 9 3 6
output
1 3
2
input
5
1 3 5 7 9
output
1 4
1
input
5
2 3 5 7 11
output
5 0
1 2 3 4 5
Note In the first sample the pair of numbers is right, as numbers 6,?9,?3 are divisible by 3.
In the second sample all numbers are divisible by number 1.
In the third sample all numbers are prime, so conditions 1 and 2 are true only for pairs of numbers (1,?1), (2,?2), (3,?3), (4,?4), (5,?5).
?
?
求出一个最长的序列,使得序列中存在一个所有数的公约数
?
#include
#include
#include
#include
#include
#define N 300009 using namespace std; int a[N]; int n; int ans[N]; int main() { while(~scanf("%d",&n)) { for(int i=1;i<=n;i++) scanf("%d",&a[i]); int le,ri,tmp=-1,num=0; for(int i=1;i<=n;) { le=ri=i; while(le && a[le]%a[i]==0) le--; while(ri<=n && a[ri]%a[i]==0) ri++; i=ri; ri=ri-le-2; if(ri>tmp) { num=0; tmp=ri; } if(ri==tmp) ans[num++]=le+1; } printf("%d %d\n",num,tmp); for(int i=0;i
?
?
?
?
?
?