计算某天是一年中的第几天 很经典

2014-11-24 12:15:11 · 作者: · 浏览: 1

很经典的题目:

当给你某个日期,让你计算该日期在该年中时第几天。

这里可以巧用switch语句。

程序如下:

[cpp]
int t_nMon;
int t_nDay;
cout << "输入月:";
cin >> t_nMon;
cout << "输入天:";
cin >> t_nDay;
int s_ndays = 0;

switch(t_nMon-1)
{
case 12:s_ndays += 31;
case 11:s_ndays += 30;
case 10:s_ndays += 31;
case 9:s_ndays += 30;
case 8:s_ndays += 31;
case 7:s_ndays += 31;
case 6:s_ndays += 30;
case 5:s_ndays += 31;
case 4:s_ndays += 30;
case 3:s_ndays += 31;
case 2:s_ndays += 28;
case 1:s_ndays += 31;
}

s_ndays = s_ndays + t_nDay;
cout << s_ndays <
摘自 Leeboy_Wang的专栏