Balloon Comes!

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 20356 Accepted Submission(s): 7673

Problem Description The contest starts now! How excited it is to see balloons floating around. You, one of the best programmers in HDU, can get a very beautiful balloon if only you have solved the very very very... easy problem.
Give you an operator (+,-,*, / --denoting addition, subtraction, multiplication, division respectively) and two positive integers, your task is to output the result.
Is it very easy?
Come on, guy! PLMM will send you a beautiful Balloon right now!
Good Luck!

Input Input contains multiple test cases. The first line of the input is a single integer T (0
Output For each case, print the operation result. The result should be rounded to 2 decimal places If and only if it is not an integer.

Sample Input

Sample Output

解题思路：水。直接的就是简单的四则运算。不过要注意，最大的坑在于：当两数相除时，若能整除，则要输出整数，否则输出两位小数。

AC代码：

#include 
   
    
#include 
    
      using namespace std; int main(){ // freopen("in.txt", "r", stdin); int n, a, b; char p[2]; scanf("%d", &n); for(int i=0; i

HDU 1170 Balloon Comes!

Balloon Comes!