题目链接：Valid Sudoku

Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules.

The Sudoku board could be partially filled, where empty cells are filled with the character '.'.

Note:

A valid Sudoku board (partially filled) is not necessarily solvable. Only the filled cells need to be validated.

这道题的要求是检测数独是否有效，其中空位置用‘.’填充，部分填充的只检测有数字的部分。

这道题比较简单，可以使用3个数组记录每行、每列、每个九宫格出现过的数字，然后遍历数独的数组即可。遇到数字时，检测对应行、对应列以及对应九宫格是否已经出现过该数字，如果出现，返回false；否则，将对应行、对应列以及对应九宫格的该数字位置标记为1。

时间复杂度：O(n2)

空间复杂度：O(n2)

 1 class Solution
 2 {
 3 public:
 4     bool isValidSudoku(vector
   
     > &board) 5 { 6 int used1[9][9] = {0}, used2[9][9] = {0}, used3[9][9] = {0}; 7 8 for(int i = 0; i < board.size(); ++ i) 9 for(int j = 0; j < board[i].size(); ++ j) 10 if(board[i][j] != '.') 11 { 12 int num = board[i][j] - '0' - 1, k = i / 3 * 3 + j / 3; 13 if(used1[i][num] || used2[j][num] || used3[k][num]) 14 return false; 15 used1[i][num] = used2[j][num] = used3[k][num] = 1; 16 } 17 18 return true; 19 } 20 };
   

转载请说明出处：LeetCode --- 36. Valid Sudoku