Binary String Matching

描述

Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110110’ while the pattern string A is ‘11’, you should output 3, because the pattern A appeared at the posit

输入

The first line consist only one integer N, indicates N cases follows. In each case, there are two lines, the first line gives the string A, length (A) <= 10, and the second line gives the string B, length (B) <= 1000. And it is guaranteed that B is always longer than A.

输出

For each case, output a single line consist a single integer, tells how many times do B appears as a substring of A.

样例输入

3
11
1001110110
101
110010010010001
1010
110100010101011 

样例输出

3
0
3 

//******BF算法***********/ 
#include
       
        
#include
        
          #include
         
           #include
          
            #include
           
             using namespace std; #define MAXSTRLEN 1000 int main() { char s[MAXSTRLEN+10]; char t[11]; int T; scanf("%d",&T); while(T--) { scanf("%s %s",t,s); int j=0,i=0; int len_s=strlen(s); int len_t=strlen(t); int count=0; while(i<=len_s) { if(s[i]==t[j]) { ++i; ++j; if(j==len_t) { count++; i=i-len_t+1; j=0; } } else { i=i-j+1; j=0; } } printf("%d\n",count); } return 0; } 
           
          
         
        
       

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