a letter and a number 时间限制：3000 ms | 内存限制：65535 KB 难度：1
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描述
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we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).
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输入
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On the first line, contains a number T(0
输出
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for each case, you should the result of y+f(x) on a line
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样例输入
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6
R 1
P 2
G 3
r 1
p 2
g 3
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样例输出
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19
18
10
-17
-14
-4
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代码:
[objc] view plaincopyprint?
- #include
int main()
- { int t,y;
- char ch; scanf("%d",&t);
- while(t--) {
- getchar(); //注意字符输入时可能出现的问题,否则ch可能会接收'\n'; scanf("%c%d",&ch,&y);
- if(ch>='a'&&ch<='z') printf("%d\n",y-(ch-'a'+1));
- else printf("%d\n",y+(ch-'A'+1));
- } return 0;
- }
<script type="text/java script">
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<script type="text/java script">BAIDU_CLB_fillSlot("771048");
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