Little X has n distinct integers: p1,?p2,?...,?pn. He wants to divide all of them into two sets A and B. The following two conditions must be satisfied:

• If number x belongs to set A, then number a?-?x must also belong to set A.
• If number x belongs to set B, then number b?-?x must also belong to set B.

  Help Little X divide the numbers into two sets or determine that it's impossible.

  Input

  The first line contains three space-separated integers n,?a,?b (1?≤?n?≤?105; 1?≤?a,?b?≤?109). The next line contains n space-separated distinct integers p1,?p2,?...,?pn (1?≤?pi?≤?109).

  Output

  If there is a way to divide the numbers into two sets, then print "YES" in the first line. Then print n integers: b1,?b2,?...,?bn (bi equals either 0, or 1), describing the division. If bi equals to 0, then pi belongs to set A, otherwise it belongs to set B.

  If it's impossible, print "NO" (without the quotes).

  Sample test(s) input

  4 5 9
  2 3 4 5
  

  output

  YES
  0 0 1 1
  

  input

  3 3 4
  1 2 4
  

  output

  NO
  

  Note

  It's OK if all the numbers are in the same set, and the other one is empty.

  
  题意：RT
  思路：据说这题的解法有很多，说一种比较简单的方法
  如果两个数字相加等于a或b，就在它们之间连一条边
  所以对于每个点，度数最多为2
  那么每个点在图中只有两种情况，要么属于一个简单环，要么属于一条链
  现在就只判断环或链里面点的数量，如果为偶数一定可以两两匹配
  如果为奇数，则要分情况，因为可能有的点有自环，因为自己是可以和自己相加属于a或b的
  如果有自环，则一定可以，将那个点拿出来，剩下的偶数个点两两匹配，否则一定不可以
  然后注意一下细节就好了~