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HDU1542_Atlantis(扫描线/线段树+离散)
2015-07-20 17:56:11 来源: 作者: 【 】 浏览:4
Tags:HDU1542_Atlantis 扫描 线段 离散

解题报告

题目传送门

题意:

求矩形并面积。

思路:

离散+线段树+扫描线。

#include 
  
   
#include 
   
     #include 
    
      #include 
     
       using namespace std; struct Seg { int v; double h,lx,rx; friend bool operator < (Seg a,Seg b) { return a.h
      
       r||qr
       
        

Atlantis

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6942 Accepted Submission(s): 3046


Problem Description There are several ancient Greek texts that contain descriptions of the fabled island Atlantis. Some of these texts even include maps of parts of the island. But unfortunately, these maps describe different regions of Atlantis. Your friend Bill has to know the total area for which maps exist. You (unwisely) volunteered to write a program that calculates this quantity.

Input The input file consists of several test cases. Each test case starts with a line containing a single integer n (1<=n<=100) of available maps. The n following lines describe one map each. Each of these lines contains four numbers x1;y1;x2;y2 (0<=x1
The input file is terminated by a line containing a single 0. Don’t process it.
Output For each test case, your program should output one section. The first line of each section must be “Test case #k”, where k is the number of the test case (starting with 1). The second one must be “Total explored area: a”, where a is the total explored area (i.e. the area of the union of all rectangles in this test case), printed exact to two digits to the right of the decimal point.

Output a blank line after each test case.

Sample Input
2
10 10 20 20
15 15 25 25.5
0

Sample Output
Test case #1
Total explored area: 180.00 

Source Mid-Central European Regional Contest 2000

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