火车进站，模拟一个栈的操作，额外的栈操作，查看是否能按照规定顺序出栈。

数据量很少，故此题目很容易AC。

直接使用数组模拟就好。

#include 
  
   
const int MAX_N = 10;

char inOrder[MAX_N], outOrder[MAX_N], stk[MAX_N];
bool rs[MAX_N<<2];
int n;

int main()
{
	while (scanf("%d", &n) != EOF)
	{
		scanf("%s %s", inOrder, outOrder);

		int j = 0, out = 0, i = 0, st = 0;
		bool possible = true;
		while (possible && !(st == 0 && out == n))
		{
			for (; i < n && inOrder[i] != outOrder[out]; i++)
			{
				rs[j++] = true;
				stk[st++] = inOrder[i];
			}//push in
			i++;//Watch out: don't forget while inOrder[i]==outOrder[out]!
			rs[j++] = true;
			rs[j++] = false;
			out++;

			while (st > 0 && stk[st-1] == outOrder[out])
			{
				st--; out++;
				rs[j++] = false;
			}//pop back

			int k = 0;//check possible
			for (; k < st && stk[k] != outOrder[out]; k++);
			if (k < st) possible = false;
		}
		if (possible)
		{
			puts("Yes.");
			for (int i = 0; i < j; i++)
			{
				if (rs[i]) puts("in");
				else puts("out");
			}
		}
		else puts("No.");
		puts("FINISH");
	}
	return 0;
}
  

解法二：

#include 
  
   
const int MAX_N = 10;

char inOrder[MAX_N], outOrder[MAX_N], stk[MAX_N];
bool rs[MAX_N<<2];
int n;

int main()
{
	while (scanf("%d", &n) != EOF)
	{
		scanf("%s %s", inOrder, outOrder);

		int j = 0, out = 0, i = 0, st = 0;
		while (i
   
     0 && stk[st-1] == outOrder[out]) { st--; out++; rs[j++] = false; }//pop back } if (st == 0 && out == n) { puts("Yes."); for (int i = 0; i < j; i++) { if (rs[i]) puts("in"); else puts("out"); } } else puts("No."); puts("FINISH"); } return 0; }