Android手机晃动事件实例

2014-11-24 10:44:20 ? 作者: ? 浏览: 0

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事件触发
public final SensorEventListener mySensorEventListener = new SensorEventListener() {


@Override
public void onAccuracyChanged(android.hardware.Sensor sensor,
int accuracy) {
// TODO Auto-generated method stub


}


@Override
public void onSensorChanged(SensorEvent event) {
// TODO Auto-generated method stub
if (event.sensor.getType() == android.hardware.Sensor.TYPE_ACCELEROMETER) {


// 获取加速度传感器的三个参数


float x = event.values[SensorManager.DATA_X];


float y = event.values[SensorManager.DATA_Y];


float z = event.values[SensorManager.DATA_Z];


// 获取当前时刻的毫秒数


curTime = System.currentTimeMillis();


// 100毫秒检测一次


float aa = curTime - lastTime;


if ((curTime - lastTime) > 100) {


duration = (curTime - lastTime);


// 看是不是刚开始晃动


if (last_x == 0.0f && last_y == 0.0f && last_z == 0.0f) {


// last_x、last_y、last_z同时为0时,表示刚刚开始记录


initTime = System.currentTimeMillis();


} else {


// 单次晃动幅度


shake = (Math.abs(x - last_x) + Math.abs(y - last_y) + Math
.abs(z - last_z));
// / duration * 1000;


}


// 把每次的晃动幅度相加,得到总体晃动幅度


totalShake += shake;


// 判断是否为摇动


if (shake > 20) {
action();
onVibrator();


initShake();
}
last_x = x;


last_y = y;


last_z = z;


lastTime = curTime;


}


}
}
};


其中 onVibrator();是触发震动 :


private void onVibrator() {
Vibrator vibrator = (Vibrator) context
.getSystemService(Context.VIBRATOR_SERVICE);
if (vibrator == null) {
Vibrator localVibrator = (Vibrator) context.getApplicationContext()
.getSystemService("vibrator");
vibrator = localVibrator;
}
vibrator.vibrate(100L);
}


掉用系统震动这样反应快 ,自己写的long数组


调用有时间间隔,效果不好



initShake();初始化事件触发的几个变量:



public void initShake() {


lastTime = 0;


duration = 0;


curTime = 0;


initTime = 0;


last_x = 0.0f;


last_y = 0.0f;


last_z = 0.0f;


shake = 0.0f;


totalShake = 0.0f;


}


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