设为首页 加入收藏

TOP

sql:MySQL 6.7 表,视图,存储过程结构查询(一)
2015-11-21 02:09:08 来源: 作者: 【 】 浏览:3
Tags:sql:MySQL 6.7 视图 存储 过程 结构 查询
#数据库MySQL 6.7

use sakila;
#查询表名
show tables;
#
SELECT TABLE_NAME,TABLE_ROWS FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA='sakila';

select column_name from information_schema.columns where table_schema='sakila' and table_name='actor';
#表结构 字段名, 类型,长度
select * from information_schema.columns where table_schema='sakila' and table_name='actor';

# GetTables
SELECT TABLE_NAME, '' OWNER, CREATE_TIME FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA = 'sakila' AND TABLE_TYPE = 'BASE TABLE' ORDER BY 1;
#GetTableColumns
SELECT COLUMN_NAME, DATA_TYPE, CHARACTER_OCTET_LENGTH, NUMERIC_PRECISION, NUMERIC_SCALE, CASE IS_NULLABLE WHEN 'NO' THEN 0 ELSE 1 END IS_NULLABLE, COLUMN_TYPE FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = 'sakila' AND TABLE_NAME = 'address' ORDER BY ORDINAL_POSITION;
#GetViews
SELECT TABLE_NAME, '' OWNER, CREATE_TIME FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA = 'sakila' AND TABLE_TYPE = 'VIEW' ORDER BY 1;
#GetViewColumns
SELECT COLUMN_NAME, DATA_TYPE, CHARACTER_OCTET_LENGTH, NUMERIC_PRECISION, NUMERIC_SCALE, CASE IS_NULLABLE WHEN 'NO' THEN 0 ELSE 1 END IS_NULLABLE, COLUMN_TYPE FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = 'sakila' AND TABLE_NAME = 'actor_info' ORDER BY ORDINAL_POSITION;
#GetTablePrimaryKey
SELECT t1.CONSTRAINT_NAME, t1.COLUMN_NAME FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE t1 INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS t2 ON t2.TABLE_SCHEMA = t1.TABLE_SCHEMA  AND t2.TABLE_NAME = t1.TABLE_NAME AND t2.CONSTRAINT_NAME = t1.CONSTRAINT_NAME WHERE t1.TABLE_SCHEMA = 'sakila' AND t1.TABLE_NAME = 'address' AND t2.CONSTRAINT_TYPE = 'PRIMARY KEY' ORDER BY t1.ORDINAL_POSITION;
#GetTableIndexes
SELECT INDEX_NAME, COUNT(*) AS COLUMN_COUNT, MAX(NON_UNIQUE) NON_UNIQUE,  CASE INDEX_NAME WHEN 'PRIMARY' THEN 1 ELSE 0 END IS_PRIMARY
FROM INFORMATION_SCHEMA.STATISTICS
WHERE  TABLE_SCHEMA = 'sakila' AND TABLE_NAME = 'customer'
GROUP BY INDEX_NAME
ORDER BY INDEX_NAME;

SELECT INDEX_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.STATISTICS
WHERE  TABLE_SCHEMA = 'sakila' AND TABLE_NAME = 'customer'
ORDER BY INDEX_NAME, SEQ_IN_INDEX;
#GetMyTableKeys
SELECT CONSTRAINT_NAME
                 FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS t1
                 WHERE t1.TABLE_SCHEMA = 'sakila' AND t1.TABLE_NAME = 'customer'
                  AND CONSTRAINT_TYPE = 'FOREIGN KEY';

 SELECT t1.CONSTRAINT_NAME, t1.COLUMN_NAME, t1.POSITION_IN_UNIQUE_CONSTRAINT,t1.REFERENCED_TABLE_NAME, REFERENCED_COLUMN_NAME
                FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE t1
                  INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS t2
                  ON t2.TABLE_SCHEMA = t1.TABLE_SCHEMA
                 AND t2.TABLE_NAME = t1.TABLE_NAME
                  AND t2.CONSTRAINT_NAME = t1.CONSTRAINT_NAME
                 WHERE t1.TABLE_SCHEMA = 'sakila' AND t1.TABLE_NAME = 'customer'
                  AND t2.CONSTRAINT_TYPE = 'FOREIGN KEY'
                ORDER BY t1.CONSTRAINT_NAME, t1.POSITION_IN_UNIQUE_CONSTRAINT;

#GetOthersTableKeys
SELECT DISTINCT CONSTRAINT_NAME
                 FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE t1
                 WHERE t1.TABLE_SCHEMA = 'sakila' AND t1.REFERENCED_TABLE_NAME = 'customer';

                 SELECT t1.CONSTRAINT_NAME, t1.TABLE_NAME, t1.COLUMN_NAME, t1.POSITION_IN_UNIQUE_CONSTRAINT, t1.REFERENCED_TABLE_NAME, REFERENCED_COLUMN_NAME
                 FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE t1
                  INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS t2
                  ON t2.TABLE_SCHEMA =
首页 上一页 1 2 下一页 尾页 1/2/2
】【打印繁体】【投稿】【收藏】 【推荐】【举报】【评论】 【关闭】 【返回顶部
分享到: 
上一篇MS SQL按IN()内容排序 下一篇SQLSERVER不能修改表结构、列类型..

评论

帐  号: 密码: (新用户注册)
验 证 码:
表  情:
内  容: