1.原始数据列：
手机号码，日期，数量
2.decode查询结果列：
手机号码，10月1日数量总和，10月2日数量总和。。。10月7日数量总和
select distinct recommender,
sum(decode(to_char(handel_date, 'yyyy-mm-dd'), '2012-10-01', 1, 0)) num,
sum(decode(to_char(handel_date, 'yyyy-mm-dd'), '2012-10-02', 1, 0)) num,
sum(decode(to_char(handel_date, 'yyyy-mm-dd'), '2012-10-03', 1, 0)) num,
sum(decode(to_char(handel_date, 'yyyy-mm-dd'), '2012-10-04', 1, 0)) num,
sum(decode(to_char(handel_date, 'yyyy-mm-dd'), '2012-10-05', 1, 0)) num,
sum(decode(to_char(handel_date, 'yyyy-mm-dd'), '2012-10-06', 1, 0)) num,
sum(decode(to_char(handel_date, 'yyyy-mm-dd'), '2012-10-07', 1, 0)) num
from rurality_recommenddg t www.2cto.com
where t.status = '3'
and t.handel_date > to_date('2012-10-01', 'yyyy-mm-dd')
and t.handel_date < to_date('2012-10-08', 'yyyy-mm-dd')
group by recommender;