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7月5号第二次直播学习笔记(二)
2018-10-19 16:55:33 】 浏览:77
Tags:7月 第二 直播 学习 笔记
2[0]) res2
= abs(rgb1[1] - rgb2[1]) res3 = abs(rgb1[2] - rgb2[2]) if not (res1 < threhold and res2 < threhold and res3 < threhold): print(i) if i not in v: v.append(i) stop = 0 for i in range(0, len(v)): val = i + v[0] if v[i] != val: stop = v[i] break width = stop - v[0] print(stop, v[0], width) return width def get_tracks(distance): import random exceed_distance = random.randint(0, 5) distance += exceed_distance # 先滑过一点,最后再反着滑动回来 v = 0 t = 0.2 forward_tracks = [] current = 0 mid = distance * 3 / 5 while current < distance: if current < mid: a = random.randint(1, 3) else: a = random.randint(1, 3) a = -a s = v * t + 0.5 * a * (t ** 2) v = v + a * t current += s forward_tracks.append(round(s)) # 反着滑动到准确位置 v = 0 t = 0.2 back_tracks = [] current = 0 mid = distance * 4 / 5 while abs(current) < exceed_distance: if current < mid: a = random.randint(1, 3) else: a = random.randint(-3, -5) a = -a s = -v * t - 0.5 * a * (t ** 2) v = v + a * t current += s back_tracks.append(round(s)) return {'forward_tracks': forward_tracks, 'back_tracks': list(reversed(back_tracks))} def crack(driver): # 破解滑动认证 # 1、点击按钮,得到没有缺口的图片 button = driver.find_element_by_xpath('//*[@id="embed-captcha"]/div/div[2]/div[1]/div[3]') button.click() # 2、获取没有缺口的图片 image1 = get_image(driver) # 3、点击滑动按钮,得到有缺口的图片 button = driver.find_element_by_class_name('geetest_slider_button') button.click() # 4、获取有缺口的图片 image2 = get_image(driver) # 5、对比两种图片的像素点,找出位移 distance = get_distance(image1, image2) print(distance) # # 6、模拟人的行为习惯,根据总位移得到行为轨迹 tracks = get_tracks(int(distance / 2)) # 7、按照行动轨迹先正向滑动,后反滑动 button = driver.find_element_by_class_name('geetest_slider_button') ActionChains(driver).click_and_hold(button).perform() # 正常人类总是自信满满地开始正向滑动,自信地表现是疯狂加速 for track in tracks['forward_tracks']: ActionChains(driver).move_by_offset(xoffset=track, yoffset=0).perform() # 结果傻逼了,正常的人类停顿了一下,回过神来发现,卧槽,滑过了,然后开始反向滑动 time.sleep(0.5) for back_track in tracks['back_tracks']: ActionChains(driver).move_by_offset(xoffset=back_track, yoffset=0).perform() # # # 小范围震荡一下,进一步迷惑极验后台,这一步可以极大地提高成功率 ActionChains(driver).move_by_offset(xoffset=3, yoffset=0).perform() ActionChains(driver).move_by_offset(xoffset=-3, yoffset=0).perform() # # 成功后,骚包人类总喜欢默默地欣赏一下自己拼图的成果,然后恋恋不舍地松开那只脏手 time.sleep(0.5) ActionChains(driver).release().perform() def login_luffy(username, password): driver = webdriver.Chrome('/Users/wupeiqi/drivers/chromedriver') driver.set_window_size(960, 800) try: # 1、输入账号密码回车 driver.implicitly_wait(3) driver.get('https://www.luffycity.com/login') input_username = driver.find_element_by_xpath('//*[@id="router-view"]/div/div/div[2]/div[2]/input[1]') input_pwd = driver.find_element_by_xpath('//*[@id="router-view"]/div/div/div[2]/div[2]/input[2]') input_username.send_keys(username) input_pwd.send_keys(password) # 2、破解滑动认证 crack(driver) time.sleep(10) # 睡时间长一点,确定登录成功 finally: pass # driver.close() if __name__ == '__main__': login_luffy(username='wupeiqi', password='123123123')

 

  四:总结

    通过selenium模拟人类单机浏览器的行为,破解滑动验证码,让我有get到了爬虫的一个本领,首先需要掌握selenium点击行为的一般模式,最后可以好好的参考peiqi老师的代码,作为模板用到以后的工作中,很有帮助,谢谢!下一步想再学学其他验证码的破解方式,多多益善!

  

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