poj1673 (二)

2014-11-23 21:42:24 · 作者: · 浏览: 12
point perpencenter(point a, point b, point c){ line u, v; u.a = c; u.b.x = u.a.x - a.y + b.y; u.b.y = u.a.y + a.x - b.x; v.a = b; v.b.x = v.a.x - a.y + c.y; v.b.y = v.a.y + a.x - c.x; return intersection(u, v); } //重心 //到三角形三顶点距离的平方和最小的点 //三角形内到三边距离之积最大的点 point barycenter(point a, point b, point c){ line u, v; u.a.x = (a.x + b.x) / 2; u.a.y = (a.y + b.y) / 2; u.b = c; v.a.x = (a.x + c.x) / 2; v.a.y = (a.y + c.y) / 2; v.b = b; return intersection(u, v); } //费马点 //到三角形三顶点距离之和最小的点 point fermentpoint(point a, point b, point c){ point u, v; double step = fabs(a.x) + fabs(a.y) + fabs(b.x) + fabs(b.y) + fabs(c.x) + fabs(c.y); int i, j, k; u.x = (a.x + b.x + c.x) / 3; u.y = (a.y + b.y + c.y) / 3; while (step >
1e-10) for (k = 0; k < 10; step /= 2, k++) for (i = -1; i <= 1; i++) for (j = -1; j <= 1; j++){ v.x = u.x + step*i; v.y = u.y + step*j; if (distance(u, a) + distance(u, b) + distance(u, c) > distance(v, a) + distance(v, b) + distance(v, c)) u = v; } return u; } int main() { int n; std::cin >> n; while (n--) { point a, b, c; std::cin >> a.x >> a.y >> b.x >> b.y >> c.x >> c.y; point center = perpencenter(a, b, c); printf("%.4f %.4f\n", center.x, center.y); } }