private void doReleaseShared() {
for (;;) {
// 获取CLH队列的头节点
Node h = head;
// 如果头节点不为null,并且头节点不等于tail节点。
if (h != null && h != tail) {
// 获取头节点对应的线程的状态
int ws = h.waitStatus;
// 如果头节点对应的线程是SIGNAL状态,则意味着“头节点的下一个节点所对应的线程”需要被unpark唤醒。
if (ws == Node.SIGNAL) {
// 设置“头节点对应的线程状态”为空状态。失败的话,则继续循环。
if (!compareAndSetWaitStatus(h, Node.SIGNAL, 0))
continue;
// 唤醒“头节点的下一个节点所对应的线程”。
unparkSuccessor(h);
}
// 如果头节点对应的线程是空状态,则设置“文件点对应的线程所拥有的共享锁”为其它线程获取锁的空状态。
else if (ws == 0 &&
!compareAndSetWaitStatus(h, 0, Node.PROPAGATE))
continue; // loop on failed CAS
}
// 如果头节点发生变化,则继续循环。否则,退出循环。
if (h == head) // loop if head changed
break;
}
}
4、非公平信号量的释放
protected int tryAcquireShared(int acquires) {
return nonfairTryAcquireShared(acquires);
}
final int nonfairTryAcquireShared(int acquires) {
for (;;) {
// 设置可以获得的信号量的许可数
int available = getState();
// 设置获得acquires个信号量许可之后,剩余的信号量许可数
int remaining = available - acquires;
// 如果剩余的信号量许可数>=0,则设置可以获得的信号量许可数为remaining
if (remaining < 0 ||
compareAndSetState(available, remaining))
return remaining;
}
}
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Semaphore;
public class SemaphoreTest1 {
private static final int SEM_MAX = 10;
public static void main(String[] args) {
Semaphore sem = new Semaphore(SEM_MAX);
//创建线程池
ExecutorService threadPool = Executors.newFixedThreadPool(3);
//在线程池中执行任务
threadPool.execute(new MyThread(sem, 5));
threadPool.execute(new MyThread(sem, 4));
threadPool.execute(new MyThread(sem, 7));
//关闭池
threadPool.shutdown();
}
}
class MyThread extends Thread {
private volatile Semaphore sem; // 信号量
private int count; // 申请信号量的大小
MyThread(Semaphore sem, int count) {
this.sem = sem;
this.count = count;
}
public void run() {
try {
// 从信号量中获取count个许可
sem.acquire(count);
Thread.sleep(2000);
System.out.println(Thread.currentThread().getName() + " acquire count="+count);
} catch (InterruptedException e) {
e.printStackTrace();
} finally {
// 释放给定数目的许可,将其返回到信号量。
sem.release(count);
System.out.println(Thread.currentThread().getName() + " release " + count + "");
}
}
}某一次运行后的结果如下:
pool-1-thread-1 acquire count=5 pool-1-thread-2 acquire count=4 pool-1-thread-1 release 5 pool-1-thread-2 release 4 pool-1-thread-3 acquire count=7 pool-1-thread-3 release 7