MySQL分区表partition线上修改分区字段(二)
MAXVALUE)
);
alter table structure，add a new partition block
ALTER TABLE employees_by_lname PARTITION BY RANGE COLUMNS (lname) (
PARTITION p0 VALUES LESS THAN ('g'),
PARTITION p1 VALUES LESS THAN ('m'),
PARTITION p2 VALUES LESS THAN ('t'),
PARTITION p3 VALUES LESS THAN ('u'),
PARTITION p4 VALUES LESS THAN (MAXVALUE)
);
4 List columns partitioning
character column
CREATE TABLE customers_1 (
first_name VARCHAR(25),
last_name VARCHAR(25),
street_1 VARCHAR(30),
street_2 VARCHAR(30),
city VARCHAR(15),
renewal DATE
)
PARTITION BY LIST COLUMNS(city) (
PARTITION pRegion_1 VALUES IN('Oskarshamn', 'H gsby', 'M nster s'),
PARTITION pRegion_2 VALUES IN('Vimmerby', 'Hultsfred', 'V stervik'),
PARTITION pRegion_3 VALUES IN('N ssj ', 'Eksj ', 'Vetlanda'),
PARTITION pRegion_4 VALUES IN('Uppvidinge', 'Alvesta', 'V xjo')
);
date column
CREATE TABLE customers_2 (
first_name VARCHAR(25),
last_name VARCHAR(25),
street_1 VARCHAR(30),
street_2 VARCHAR(30),
city VARCHAR(15),
renewal DATE
)
PARTITION BY LIST COLUMNS(renewal) (
PARTITION pWeek_1 VALUES IN('2010-02-01', '2010-02-02', '2010-02-03',
'2010-02-04', '2010-02-05', '2010-02-06', '2010-02-07'),
PARTITION pWeek_2 VALUES IN('2010-02-08', '2010-02-09', '2010-02-10',
'2010-02-11', '2010-02-12', '2010-02-13', '2010-02-14'),
PARTITION pWeek_3 VALUES IN('2010-02-15', '2010-02-16', '2010-02-17',
'2010-02-18', '2010-02-19', '2010-02-20', '2010-02-21'),
PARTITION pWeek_4 VALUES IN('2010-02-22', '2010-02-23', '2010-02-24',
'2010-02-25', '2010-02-26', '2010-02-27', '2010-02-28')
);
5 HASH Partitioning
int column,it can use digital function
CREATE TABLE employeesint (
id INT NOT NULL,
fname VARCHAR(30),
lname VARCHAR(30),
hired DATE NOT NULL DEFAULT '1970-01-01',
separated DATE NOT NULL DEFAULT '9999-12-31',
job_code INT,
store_id INT
)
PARTITION BY HASH(MOD(store_id,4))
PARTITIONS 4;
If you do not include a PARTITIONS clause, the number of partitions defaults to 1. as below:
CREATE TABLE employeestest (
id INT NOT NULL,
fname VARCHAR(30),
lname VARCHAR(30),
hired DATE NOT NULL DEFAULT '1970-01-01',
separated DATE NOT NULL DEFAULT '9999-12-31',
job_code INT,
store_id INT
)
PARTITION BY HASH(store_id);
date colum
CREATE TABLE employees2 (
id INT NOT NULL,
fname VARCHAR(30),
lname VARCHAR(30),
hired DATE NOT NULL DEFAULT '1970-01-01',
separated DATE NOT NULL DEFAULT '9999-12-31',
job_code INT,
store_id INT
)
PARTITION BY HASH( YEAR(hired) )
PARTITIONS 4;
truncate all data rows: alter table rcx truncate PARTITION;
6 LINEAR HASH Partitioning
CREATE TABLE employees_linear (
id INT NOT NULL,
fname VARCHAR(30),
lname VARCHAR(30),
hired DATE NOT NULL DEFAULT '1970-01-01',
separated DATE NOT NULL DEFAULT '9999-12-31',
job_code INT,
store_id INT
)
PARTITION BY LINEAR HASH( YEAR(hired) )
PARTITIONS 4;
Given an expression expr, the partition in which the record is stored when linear hashing is used is partition number N from among num partitions, where N is derived according to the following algorithm: