代码实现:
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#includeint main() { double a=0.0,b=0.0; double c=0.0; double sum=0.0; scanf("%lf %lf",&a,&b); c=(a-b)/2.0; if (c<=0) { sum=b+c; } else { sum=c+b; } printf("%lf\n",sum); return 0; }
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输入:1 2
结果为:1.500000
#includeint main() { double a=0.0,b=0.0; double c=0.0; double sum=0.0; scanf("%lf %lf",&a,&b); c=(a-b)/2.0; if (c<=0) { sum=b+c; } else { sum=c+b; } printf("%lf\n",sum); return 0; }
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