C/C++中int/long/float/double数值类型与字符串互相转换

2014-11-24 00:36:30 · 作者: · 浏览: 41
一、int/long/float/double 转 字符串
方法1:itoa, ltoa(a表示array数组的意思)

头文件:stdlib.h

示例:

int a = 3;

long b = 23;

char buf1[30] = "";
itoa(a, buf1, 10);//10表示十进制,buf1保存的内容为"3"
char buf2[30] = "";
ltoa(b, buf2, 10);//10表示十进制,buf2保存的内容为"32"
方法2:sprintf

头文件:stdio.h

示例:

int a = 3;
float b = 4.2f;
char buf[30] = "";
sprintf(buf, "%d,%f", a, b);//buf保存的内容为"3,4.2",可对比printf
方法3:ostringstream

头文件:#include

using namespace std;

示例:

int a = 3;
float b = 4.2f;
ostringstream s1;
s1< string s2 = s1.str();//s2保存的内容为"3,4.2"
二、字符串 转 int/long/float/double


方法1:atoi,atol,atof

头文件:stdlib.h

示例:

int a = atoi("32");

long b = atol("333");

double c = atof("23.4");
方法2:strtol, strtod

头文件:stdlib.h

示例:

long b = strtol("333", NULL, 10);//10表示十进制

double c = strtod("32.3", NULL);


方法3:sscanf

头文件:stdio.h

示例:

int a;
float b;
sscanf("23 23.4", "%d %f", &a, &b);//对比scanf
方法4:istringstream

头文件:#include

using namespace std;

示例:

int a;
float b;
istringstream s1("23 23.4");
s1>>a>>b;//对比cin


摘自 Justme0的专栏