HDU 4847 陕西邀请赛A(水)

2015-07-24 05:38:35 · 作者: · 浏览: 7

HDU 4847 Wow! Such Doge!

题目链接

题意:给定文本,求有几个doge,不区分大小写

思路:水题,直接一个个读字符每次判断即可

代码:

#include 
  
   
#include 
   
     char c; char a[5]; int main() { a[5] = '\0'; int ans = 0; while ((c = getchar()) != EOF) { if (c >= 'a' && c <= 'z') c -= 32; a[3] = c; if (strcmp(a, "DOGE") == 0) ans++; for (int i = 0; i < 3; i++) a[i] = a[i + 1]; } printf("%d\n", ans); return 0; }