LeetCode――ZigZag Conversion

2015-07-24 05:43:00 · 作者: · 浏览: 9

The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R
And then read line by line: "PAHNAPLSIIGYIR"

Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);

convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

字符串的弯曲转换。

要做的首先就是发现每一行的规律,可以发现,每一行有2 * nRows - 2个字符。把结果的列先加入到新的字符串中,再加入行。

    public String convert(String s, int nRows) {
        if(nRows <= 1)
            return s;
        StringBuffer buf = new StringBuffer();
        int period = 2 * nRows - 2;
        for(int i=0;i