Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg", "add", return true.
Given "foo", "bar", return false.
Given "paper", "title", return true.
Note:
You may assume both s and t have the same length.
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bool isIsomorphic(char* s, char* t) {
int letter1[256] = { 0 };
for (int i = 0; s[i] != '\0'; i++) {
if (!letter1[s[i]]) letter1[s[i]] = t[i];
else if (letter1[s[i]] != t[i]) return false;
}
int letter2[256] = { 0 };
for (int i = 0; t[i] != '\0'; i++) {
if (!letter2[t[i]]) letter2[t[i]] = s[i];
else if (letter2[t[i]] != s[i]) return false;
}
return true;
}
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