HDU 3549 Flow Problem(有向边网络流)

2014-11-23 21:58:40 · 作者: · 浏览: 7
题意:T个测试数据
下面n,m表示n个点m条有向带权边
m条边
问:从1-n最大流多少
测板子的题目,没啥思路
下面用的是dinic,开始没有考虑反向弧debug了好久,附赠一大坨测试数据
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#define inf 100000000
#define eps 1e-8
#define N 205
#define M 1050
#define ll int
using namespace std;
inline ll Max(ll a,ll b){return a>b a:b;}
inline ll Min(ll a,ll b){return aQ;	while(!Q.empty())Q.pop();
	Q.push(Start);	dis[Start]=0;	vis[Start]=1;
	while(!Q.empty())
	{
		int u = Q.front(); Q.pop();
		for(int i=head[u];i!=-1;i=edge[i].nex){
			Edge E =edge[i];
			if(!vis[E.to] && E.cap>E.flow)
			{
				vis[E.to]=1;
				dis[E.to]=dis[u]+1;
				if(E.to==End)return true;
				Q.push(E.to);
			}
		}
	}
	return false;
}
int DFS(int x, int a,int End){//流入x 的流量是a
	if(x==End || a==0)return a;
	int flow = 0, f;
	for(int& i=cur[x];i!=-1;i=edge[i].nex)
	{
		Edge& E = edge[i];
		if(dis[x]+1 == dis[E.to] && (f = DFS(E.to , Min(a, E.cap-E.flow), End))>
0 ) { E.flow += f; edge[ i^1 ].flow -= f;//反向边要减掉 flow += f; a -= f; if(a==0)break; } } return flow; } int Maxflow(int Start,int End){ int flow=0; while(BFS(Start,End)){ memcpy(cur,head,sizeof(head));//把head的数组复制过去 flow += DFS(Start, inf, End); } return flow; } int main() { int T,Cas=1,n,m,i,a,b,c;scanf("%d",&T); while (T--) { memset(head,-1,sizeof(head)); edgenum=0; scanf("%d %d",&n,&m); while(m--) { scanf("%d %d %d",&a,&b,&c); addedge(a,b,c); } printf("Case %d: %d\n",Cas++,Maxflow(1,n)); } return 0; } /* 99 3 2 1 2 1 2 3 1 3 3 1 2 1 2 3 1 1 3 1 3 2 1 3 2 1 3 5 3 2 1 2 456 1 2 56431 3 3 1 3 100 1 1 100 1 1 100 11 15 1 2 1 1 3 1 1 4 1 2 5 1 2 6 1 3 7 1 3 8 1 4 9 1 4 10 1 5 11 1 6 11 1 7 11 1 8 11 1 9 11 1 10 11 1 11 15 1 2 2 1 3 2 1 4 2 2 5 1 2 6 1 3 7 1 3 8 1 4 9 1 4 10 1 5 11 1 6 11 1 7 11 1 8 11 1 9 11 1 10 11 1 11 15 1 2 2 1 3 1 1 4 2 2 5 1 2 6 1 3 7 1 3 8 1 4 9 1 4 10 1 5 11 1 6 11 1 7 11 1 8 11 1 9 11 1 10 11 1 2 0 2 1 1 2 4651 4 4 1 2 10 2 1 5 2 4 20 1 3 3 4 5 1 2 10 2 1 5 2 4 20 1 3 3 3 4 1 9 10 1 5 2 2 4 6 2 3 4 1 2 9 3 9 5 5 9 4 2 3 1 4 2 1 6 7 1 3 7 2 4 4 1 2 10 1 3 2 3 4 1 2 4 1 4 4 1 2 1 1 3 1 3 4 10 2 4 10 ans: 1 2 7 0 100 3 6 5 0 4651 10 11 7 2 2 */