[leetcode]Binary Tree Level Order Traversal II

Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root).

For example:
Given binary tree {3,9,20,#,#,15,7},

3
/ \
9 20
/ \
15 7

return its bottom-up level order traversal as:

[
[15,7]
[9,20],
[3],
] /**

* Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */ 
class Solution { 
public: 
    vector > levelOrderBottom(TreeNode *root) { 
        // Start typing your C/C++ solution below  
        // DO NOT write int main() function  
        stack> s; 
        if(!root) return vector>(); 
         
        queue q1,q2; 
        q1.push(root); 
         
        TreeNode *cur; 
        vector tmp; 
         
        while(!q1.empty()){ 
            tmp.clear(); 
            while(!q1.empty()){ 
                cur = q1.front(); 
                q1.pop(); 
                 
                tmp.push_back(cur -> val); 
                if(cur -> left) q2.push(cur -> left); 
                if(cur -> right) q2.push(cur -> right); 
            } 
            s.push(tmp); 
            swap(q1, q2); 
        } 
         
        vector curVec; 
        vector> result; 
        while(!s.empty()){ 
            curVec = s.top(); 
            s.pop(); 
            result.push_back(curVec); 
        } 
        return result; 
         
    } 
         
     
}; 

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    vector > levelOrderBottom(TreeNode *root) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        stack> s;
        if(!root) return vector>();
       
        queue q1,q2;
        q1.push(root);
       
        TreeNode *cur;
        vector tmp;
       
        while(!q1.empty()){
            tmp.clear();
            while(!q1.empty()){
                cur = q1.front();
                q1.pop();
               
                tmp.push_back(cur -> val);
                if(cur -> left) q2.push(cur -> left);
                if(cur -> right) q2.push(cur -> right);
            }
            s.push(tmp);
            swap(q1, q2);
        }
       
        vector curVec;
        vector> result;
        while(!s.empty()){
            curVec = s.top();
            s.pop();
            result.push_back(curVec);
        }
        return result;
       
    }
       
   
};