hdu 3530 Subsequence(单调队列)

2014-11-24 02:00:35 · 作者: · 浏览: 5
题意:求区间最值差在[m,k]范围内的最长区间。
解法类似于hdu 4123 Bob’s Race(单调队列或者rmq)。稍微有一点点的不一样而已。
#include  
#include  
#include  
using namespace std ;  
  
const int maxn = 111111 ;  
int n , m , num[maxn] , k ;  
struct Deque {  
    int val[2][maxn], pos[2][maxn];  
    int star[2] , tail[2] ;  
    void init () {  
        star[0] = 1 ;  
        tail[0] = 0 ;  
        star[1] = 1 ;  
        tail[1] = 0 ;  
    }  
    int judge (int c, int v) {  
        return c ^ (val[c][tail[c]] < v);  
    }  
    void push (int id, int v) {  
        int i ;  
    //  printf ( "id = %d , v = %d\n" , id , v ) ;  
        for ( i = 0 ; i < 2 ; i ++ ) {  
            while ( star[i] <= tail[i] && judge ( i , v ) )  
                tail[i] -- ;  
            val[i][++tail[i]] = v ;  
            pos[i][tail[i]] = id ;  
        }  
    }  
    void pop ( int c ) {  
        if ( star[c] <= tail[c] ) star[c] ++ ;  
    }  
    int gao ( int &last ) {  
        while ( (val[0][star[0]] - val[1][star[1]] >
k ) ) { if ( pos[1][star[1]] < pos[0][star[0]] ) { last = pos[1][star[1]] ; pop ( 1 ) ; } else { last = pos[0][star[0]] ; pop ( 0 ) ; } } if ( val[0][star[0]] - val[1][star[1]] < m ) return -1 ; return last ; } } q ; int main () { int i , j ; while ( scanf ( "%d%d%d" , &n , &m , &k ) != EOF ) { for ( i = 1 ; i <= n ; i ++ ) scanf ( "%d" , &num[i] ) ; q.init () ; int ans = 0 , last = 0 ; for ( i = 1 ; i <= n ; i ++ ) { q.push ( i , num[i] ) ; int k = q.gao ( last ) ; if ( k == -1 ) continue ; last = k ; ans = max ( ans , i - last ) ; } printf ( "%d\n" , ans ) ; } return 0 ; }