1.2.4 operator调用形式

int main(int argc, char* argv[])
{
CAdd a(5),b,c(1);
b=operator+(a,1);  //调用友元函数
printf("sum is %d\n",(int)b);
printf("operator a is %d\n",(int)a);
b=a.operator +(c);   //调用成员函数
printf("sum is %d\n",(int)b);
printf("operator a is %d\n",(int)a);

 return 0;
}