C/C++ 实现取得当前时间

C/C++ 实现取得当前时间

#include
  
   
#include
   
     #include
    
      #include
     
       #include
      
        #define N 10 int main(int argc,char *argv[]) { FILE *fp; int line=0; char buf[N]; if((fp=fopen("test.txt","a"))==NULL) { fprintf(stderr,"fopen failed:%s\n",strerror(errno)); return (-1); } while(fgets(buf,N,fp)!=NULL) { if(strlen(buf)
       
        tm_year+1900, t1->tm_mon+1, t1->tm_mday, t1->tm_hour, t1->tm_min, t1->tm_sec), printf("%s",buf); fputs(buf,fp); fflush(fp); sleep(1); } fclose(fp); return 0; } 
       
      
     
    
   
  

示例效果：