如何实现深度优先遍历(DFS)

2015-07-20 17:34:14 · 作者: · 浏览: 5

DFS实现步骤如下:

①访问顶点V,并标记V已经访问

②查找V的第一个邻接顶点w

③若W存在,则继续执行,否则算法结束

④若W未被访问,则使用DFS递归访问w

⑤查找V的下一个邻接节点,并记为W,转到步骤③

\

对上图进行DFS,则访问顺序为<??http://www.2cto.com/kf/ware/vc/" target="_blank" class="keylink">vcD4KPHA+QSBCIEQgQyBFPC9wPgo8cD7KudPDzrG0+sLryOfPwqO6PC9wPgo8cD48cHJlIGNsYXNzPQ=="brush:java;">Vector G[maxn] int vis[maxn] void dfs(int u) { vis[u]=1; //设置为已经访问 int d=G[u].Size()//得到顶点u的所有邻接节点,个数为d for(int i=0;i

附上全部代码:

#include
  
   
using namespace std;
#define VertexSize 10
int visit[VertexSize];

typedef struct
{
	int weight[VertexSize][VertexSize];
}Graph;


void Initiate_Graph(Graph *g,int n)
{
	int i,j;
	for(i=0;i
   
    weight[i][j]=0; else g->weight[i][j]=0x7fff; } } void InsertEdge(Graph *g,int v,int w,int weight,int n) { if(v<0 || v>=n||w<0||w>=n) { cout<<"overflow!"<
    
     weight[v][w]=weight; } void dfs(Graph *g,int u,int n) { cout<
     
      weight[u][i]>0 && g->weight[u][i]<0x7fff && !visit[i]) { visit[i]=1; dfs(g,i,n); } } } void main() { Graph g; int n,edge; cout<<"请输入图的顶点个数:"<
      
       >n; cout<<"请输入图的边个数"<
       
        >edge; Initiate_Graph(&g,n); int i,p1,p2,weight; cout<<"请输入顶点-顶点-权值:"<
        
         >p1>>p2>>weight; InsertEdge(&g,p1,p2,weight,n); } dfs(&g,0,n); system("pause"); }