NYOJ-a letter and a number - c++编程基础

a letter and a number 时间限制：3000 ms | 内存限制：65535 KB 难度：1

描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0 输出

for each case, you should the result of y+f(x) on a line

样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

代码: [objc] view plaincopyprint?

#include int main()

{ int t,y;

char ch; scanf("%d",&t);

while(t--) {

getchar(); //注意字符输入时可能出现的问题,否则ch可能会接收'\n'; scanf("%c%d",&ch,&y);

if(ch>='a'&&ch<='z') printf("%d\n",y-(ch-'a'+1));

else printf("%d\n",y+(ch-'A'+1));

} return 0;

}

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