HDU5014:Number Sequence - c++编程基础

Problem Description There is a special number sequence which has n+1 integers. For each number in sequence, we have two rules:

● a _i ∈ [0,n]
● a _i ≠ a _j( i ≠ j )

For sequence a and sequence b, the integrating degree t is defined as follows(“?” denotes exclusive or):

t = (a ₀ ? b ₀) + (a ₁ ? b ₁) +???+ (a _n ? b _n)

(sequence B should also satisfy the rules described above)

Now give you a number n and the sequence a. You should calculate the maximum integrating degree t and print the sequence b.

Input There are multiple test cases. Please process till EOF.

For each case, the first line contains an integer n(1 ≤ n ≤ 10 ⁵), The second line contains a ₀,a ₁,a ₂,...,a _n.

Output For each case, output two lines.The first line contains the maximum integrating degree t. The second line contains n+1 integers b ₀,b ₁,b ₂,...,b _n. There is exactly one space between b _i and b _i+1 (0 ≤ i ≤ n - 1). Don’t ouput any spaces after b _n.

Sample Input

4
2 0 1 4 3

Sample Output

20
1 0 2 3 4

尽量错开对应位置的0,1即可，就是说将对应位的二进制按位取反了，当然不能用~符号
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           using namespace std; #define ll __int64 #define up(i,x,y) for(i=x;i<=y;i++) #define up2(i,x,y) for(i=x;y;i++) #define down(i,x,y) for(i=x;i>=y;i--) #define down2(i,x,y) for(i=x;y;i--) #define mem(a,b) memset(a,b,sizeof(a)) #define s(a) scanf("%d",&a) #define s64(a) scanf("%I64d",&a) #define w(a) while(a) int n,a[100005],i,hash[100005]; int main() { w(~s(n)) { up(i,0,n) s(a[i]); printf("%I64d\n",(ll)n*n+n); mem(hash,-1); down(i,n,0) { if(hash[i]>=0) continue; int num=0,s=1,t=i; w(t) { int tem=((t&1)^1); num=num+s*tem; s*=2; t=t/2; } hash[num]=i; hash[i]=num; } printf("%d",hash[a[0]]); up(i,1,n) printf(" %d",hash[a[i]]); printf("\n"); } return 0; }