Codeforces 464 C. Substitutes in Number - c++编程基础

从后往前推,记录每个数字代表的值和他的倍数....

C. Substitutes in Number time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output

Andrew and Eugene are playing a game. Initially, Andrew has string s, consisting of digits. Eugene sends Andrew multiple queries of type "di?→?ti", that means "replace all digits di in string s with substrings equal to ti". For example, if s?=?123123, then query "2?→?00" transforms s to 10031003, and query "3?→?" ("replace 3 by an empty string") transforms it to s?=?1212. After all the queries Eugene asks Andrew to find the remainder after division of number with decimal representation equal to s by 1000000007 (109?+?7). When you represent s as a decimal number, please ignore the leading zeroes; also if s is an empty string, then it's assumed that the number equals to zero.

Andrew got tired of processing Eugene's requests manually and he asked you to write a program for that. Help him!

Input

The first line contains string s (1?≤?|s|?≤?105), consisting of digits ― the string before processing all the requests.

The second line contains a single integer n (0?≤?n?≤?105) ― the number of queries.

The next n lines contain the descriptions of the queries. The i-th query is described by string "di->ti", where di is exactly one digit (from 0 to 9), ti is a string consisting of digits (ti can be an empty string). The sum of lengths of ti for all queries doesn't exceed 105. The queries are written in the order in which they need to be performed.

Output

Print a single integer ― remainder of division of the resulting number by 1000000007 (109?+?7).

Sample test(s) input

123123
1
2->00

output

10031003

input

123123
1
3->

output

input

222
2
2->0
0->7

output

input

1000000008
0

output

Note

Note that the leading zeroes are not removed from string s after the replacement (you can see it in the third sample).

#include 
  
   
#include 
   
     #include 
    
      #include 
     
       #include 
      
        using namespace std; typedef long long int LL; const LL MOD=1000000007LL; string yuan,qy[100100]; int n; LL Replace[10],Tenpow[10]; void init() { for(int i=0;i<=9;i++) { Replace[i]=i; Tenpow[i]=10; } } int main() { cin>>yuan; cin>>n; for(int i=0;i
       
        >qy[i]; init(); for(int i=n-1;i>=0;i--) { int from=qy[i][0]-'0'; LL rT=1LL,rp=0LL; for(int j=3,sz=qy[i].size();j