HDU2602Bone Collector

2015-07-20 17:56:50 · 作者: · 浏览: 4

Bone Collector

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 29685 Accepted Submission(s): 12208


Problem Description Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
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Input The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
Output One integer per line representing the maximum of the total value (this number will be less than 2 31).
Sample Input
1
5 10
1 2 3 4 5
5 4 3 2 1

Sample Output
14
简单01背包
#include
  
   
#include
   
     #include
    
      #include
     
       #include
      
        #include
       
         using namespace std; int main() { int t; scanf("%d",&t); while(t--) { int n,i,j,v; scanf("%d%d",&n,&v); int dp[1100]={0},c[1100],w[1100]; for(i=0;i
        
         =c[i];j--) { if(dp[j]