SRM 599 div2 250 500(一)

2014-11-24 08:09:56 · 作者: · 浏览: 0

Problem Statement

Dachshund is a popular dog breed. In this problem, a miniature dachshund is defined as a dachshund whose weight is not more than 5,000 grams.

Lun the miniature dachshund loves mikan (satsuma oranges). She has just bought some mikan. You are given a vector mikan. It gives the weight of all mikan she bought. For each valid i, mikan[i] is the weight of the i-th mikan in grams.

You are also given an int weight. Currently, Lun weighs weight grams. When she eats i-th mikan, her weight increases by mikan[i] grams. If she eats multiple mikan, her weight increases by their total weight. She cannot eat just a part of a mikan. In other words, if she chooses to eat a mikan, she eats it completely.

She wants to remain being a miniature dachshund. That is, she wants her weight not to exceed 5,000 grams. Under this condition, calculate and return the maximum number of mikan Lun can eat.

Definition

Class: MiniatureDachshund
Method: maxMikan
Parameters: vector , int
Returns: int
Method signature: int maxMikan(vector mikan, int weight)
(be sure your method is public)

Constraints

- mikan will contain between 1 and 50 elements, inclusive.
- Each element of mikan will be between 50 and 200, inclusive.
- weight will be between 3,000 and 5,000, inclusive.

Examples

0)
{100, 100, 100, 100, 100}
4750
Returns: 2
Here, Lun weighs 4,750 grams and has bought 5 mikan, each of which weighs 100 grams. When she eats 2 of these, her weight will be 4,950 grams. She should not eat more.
1)
{100, 100, 100, 100, 50}
4750
Returns: 3
This time, one of the mikan is smaller. She can eat it with 2 of the 100-gram mikan. Note that her weight is allowed to be exactly 5,000 grams.
2)
{120, 90, 130, 100, 110, 80}
3000
Returns: 6
When she is light enough, she can eat all of the mikan she has bought.
3)
{50}
5000
Returns: 0
When her weight is already 5,000 grams, she should not eat anything.
4)
{200, 50, 200, 50, 200, 50, 200, 50}
4800
Returns: 4

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                     using namespace std; class MiniatureDachshund { public: int maxMikan(vector 
                    
                     , int); }; int MiniatureDachshund::maxMikan(vector 
                     
                       mikan, int weight) { int t=mikan.size(),ans=0,v=5000-weight; sort(mikan.begin(),mikan.end()); for(int i=0;i
                      
                       0&&mikan[i]<=v;i++) { v-=mikan[i];ans++; } return ans; } //<%:testing-code%> //Powered by [KawigiEdit] 2.0! //<%:start-tests%>
                      
                     
                    
                   
                  
                 
                
               
              
             
            
           
          
         
        
       
      
     
   
  


Problem Statement

This problem statement contains superscipts that may not display properly outside the applet.


You are given four ints A, B, C and D. Return "divisible" (quotes for clarity) if AB is divisible by CD. Return "not divisible" otherwise.

Definition

Class: BigFatInteger2
Method: isDivisible
Parameters: int, int, int, int
Returns: string
Method signature: string isDivisible(int A, int B, int C, int D)
(be sure your method is public)

Notes