Best Time to Buy and Sell Stock II @LeetCode

package Level3;

/**
 * Best Time to Buy and Sell Stock II
 * 
 *  Say you have an array for which the ith element is the price of a given stock on day i.

Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).
 *
 */
public class S122 {

	public static void main(String[] args) {
		int[] prices = {2,1,2,0,4};
		System.out.println(maxProfit(prices));
	}

	// 贪心法，本题和前面的Best Time to Buy and Sell Stock 不同在于，本题可以多次买卖股票，
	// 从而赚取所以的价格差。因此用贪心法，基本思想是锁定一个低价，然后在价格升到局部最高点
	// （即下一天的价钱就下降了）时候，抛出股票，然后把下一天较低的价钱作为买入，接着计算。
	// 要注意最后要处理最后一次的利润
	public static int maxProfit(int[] prices) {
		if(prices.length == 0){
			return 0;
		}
        int totalProfit = 0;
        int startIndex = 0;
        int i;
        
        for(i=1; i





 prices[startIndex]){
        	totalProfit += prices[i-1] - prices[startIndex];
        }
        
        return totalProfit;
    }
}