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[20190423]那个更快的疑问3.txt(十一)
2019-09-17 18:39:41 】 浏览:194
Tags:20190423 那个 更快 疑问 3.txt
;             1                   2723          2723

--//10g:
SCOTT@test> select method,count(*),round(avg(TIME_ELA),0),sum(TIME_ELA) from job_times group by method order by 3 ;
METHOD                 COUNT(*) ROUND(AVG(TIME_ELA),0) SUM(TIME_ELA)
-------------------- ---------- ---------------------- -------------
id=unindex_name               1                   1359          1359
id=unindex                    1                   1591          1591

--//真心搞不懂,回表反而更快一些.oracle许多东西真心搞不懂....
--//感觉如果访问数据块缓存数据块,没有阻塞无需要获取cbc latch吗?

5.附上gdb脚本:
--//11g版本:
$ cat latch11g.gdb
break kslgetl
  commands
    silent
    printf "kslgetl %x, %d, %d, %d\n", $rdi, $rsi, $rdx, $rcx
    c
  end

break kslges
  commands
    silent
    printf "kslges %x, %d, %d, %d\n", $rdi, $rsi, $rdx, $rcx
    c
  end

break skgpwwait
  commands
    silent
    printf "skgpwwait %d, %d, %d, %d\n", $rdi, $rsi, $rdx, $rcx
    c
  end

break sskgpwwait
  commands
    silent
    printf "sskgpwwait %d, %d, %d, %d\n", $rdi, $rsi, $rdx, $rcx
    c
  end

break semop
  commands
    silent
    printf "semop %d, %d, %d, %d\n", $rdi, $rsi, $rdx, $rcx
    c
  end

#break *0x93f9ddc
#  commands
#    silent
#    printf " spin count loop: %d %d %x\n", $rax,$rcx,$rip
#    c
#  end

##
break kslgetsl_w
  commands
    silent
    printf "kslgetsl_w laddr:%x, willing:%d, where:%d, why:%d, mode:%d\n", $rdi, $rsi, $rdx, $rcx, $r8
    c
  end

break ksl_get_shared_latch
  commands
    silent
    printf "ksl_get_shared_latch laddr:%x, willing:%d, where:%d, why:%d, mode:%d\n", $rdi, $rsi, $rdx, $rcx, $r8
    c
  end

break kslgess
  commands
    silent
    printf "kslgess %x, %d, %d, %d\n", $rdi, $rsi, $rdx, $rcx
    c
  end

break kslskgs
  commands
    silent
    printf "kslskgs %x, %d, %d, %d\n", $rdi, $rsi, $rdx, $rcx
    c
  end

break kslfre
  commands
    silent
    printf "kslfre %x, %d, %d, %d\n
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