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VB笔试题(英文的)
2014-11-23 22:51:24 来源: 作者: 【 】 浏览:2
Tags:试题 英文

VISUAL BASIC SECTION


Q1 : Grade yourself on your Visual Basic Skill


1 ¨C poor .. 10- Advance player


Ans:


Q2 : Declare Function Multiply_Add Lib °test ± (ByRef A as integer ,VeRef B as integer , ByVal c as integer ) as integer


Q2.1: Explain what is Declare Function used for


Ans :


Q2.2 : Explain the difference between ByRef and ByVal


Ans :


Q3 : Is Visual Basic a COMPILER or an INTERPERTER


Ans


C++ SECTION


Q4 :


int iVal1 = 0, iVal2 = 0;


int * ipVal;


ipVal = &iVal1; What is the Value of ipVal = *ipVal =


ipVal = (int*)iVal1; What is the Value of ipVal = *ipVal =


iVal2 = (int)&iVal1; What is the Value of ipVal = *ipVal =


Q5:


void SwapAB(int A, int B)


{


A=B;


B=A;


}


int main()


{


int A,B;


A=1;


B=2;


SwapAB(A,B);


return 0; // A= , B=


}


What is the value of A and B


What is the difference between STRUCTURE and OBJECT ORIENTED PROGRAMMING


What is the difference between C and C++


What is an interpreter


.


Q6. Step through the following C code and answer the questions


void FillMem(unsigned char *pData, unsigned char len)


{


while (len–) *pData++ = len;


}


void main()


{


unsigned char buffer1[8];


unsigned char buffer2[8];


unsigned char * pData;


unsigned char cnt1, cnt2;


for (cnt1 = 0; cnt1 < 8; cnt1++)


buffer1[cnt1] = 0xFF;


for (cnt1 = 0; cnt1 < 8; cnt1++)


buffer2[cnt1] = 0xFF;


for (cnt1 = 0, cnt2 = 4; cnt1 < 4; cnt1++, cnt2–)


buffer1[cnt1] = cnt1;


buffer2[cnt2] = cnt2;


/***************************************************************


Q What is the content of buffer1 & buffer2


buffer1[0] = buffer2[0] =


buffer1[1] = buffer2[1] =


buffer1[2] = buffer2[2] =


buffer1[3] = buffer2[3] =


****************************************************************/


for (cnt1 = 0; cnt1 < 8; cnt1++)


buffer1[cnt1] = 0xFF;


FillMem(&buffer1[0], 4);


/***************************************************************


Q. What is the content of buffer1


buffer1[0] =


buffer1[1] =


buffer1[2] =


buffer1[3] =


****************************************************************/


for (cnt1 = 0; cnt1 < 8; cnt1++)


buffer1[cnt1] = 0xFF;


pData = &buffer1[4];


pData = pData – 2;


for (cnt1 = 0; cnt1 < 2; cnt1++)


*pData++ = cnt1;


/***************************************************************


Q. What is the content of buffer1


buffer1[0] =


buffer1[1] =


buffer1[2] =


buffer1[3] =


****************************************************************/


}


Visual Basic / C++ Section:


You can use C/C++ or Visual Basic to do the following


Please write a simple function to access the momory card 8×8 bytes


The input parameter for memory location is between 0-63


If user want to write 1 at the memory location 9, then this function will write 1 at cell (1,1)


Eg.


MemAccess(9,1); // MemAccess(int Position, int Value);


MemAccess(2,5);


Result


0


1


2


3


4


5


6


7


0


1


2


3


4


5


6


7


Note: you can use array type to define this memory card.


Eg.


Int MemoryCard[8][8]; // Array definition in C


{


}


BACK TO FOUNDATION


1 BYTE = _________BITS (based on 8 bits processor)


1 INTEGER = _______BYTES (based on 8 bits processor)


1 LONG = _________BYTES (based on 8 bits processor)


8051 ASSEMBLY LANGUAGE PROGRAMMING


Add a comment on each line !


MOV DPTR,#atable


MOV A,R7


MOVC A, @A+DPTR


CJNE A,#EEPDELIVERYSTATE,_JUMP1


RET


_JUMP1:


MOV R6,A


MOV A,R7


INC A


MOVC A, @A+DPTR


MOV DPL,A


MOV DPH,R6


POP ACC


POP ACC


CLR A


JMP @A+DPTR


Explain what is the function


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